JEE MAIN - Chemistry (2021 - 16th March Evening Shift)

1
Match List - I with List - II :

List - I
Test/Reagents/Observation(s)
List - II
Species detected
(a) Lassaigne's Test (i) Carbon
(b) Cu(II) oxide (ii) Sulphur
(c) Silver nitrate (iii) N, S, P, and halogen
(d) The sodium fusion extract
gives black precipitate with
acetic acid and lead acetate
(iv) Halogen Specifically


The correct match is :
Answer
(C)
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
2
JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 101 English
The structure of X is :
Answer
(C)
JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 101 English Option 3
3
An unsaturated hydrocarbon X on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon X is :
Answer
(A)
HC $$ \equiv $$ C $$-$$ CH2 $$-$$ CH3
4
The exact volumes of 1 M NaOH solution required to neutralise 50 mL of 1 M H3PO3 solution and 100 mL of 2 M H3PO2 solution, respectively, are :
Answer
(B)
100 mL and 200 mL
5
The characteristics of elements X, Y and Z with atomic numbers, respectively, 33, 53 and 83 are :
Answer
(C)
X is a metalloid, Y is a non-metal and Z is a metal.
6
Which of the following is least basic?
Answer
(A)
$${(C{H_3}CO)_2}\mathop N\limits^{..} H$$
7
Ammonolysis of Alkyl halides followed by the treatment with NaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOH in the reaction is :
Answer
(A)
to remove acidic impurities
8
The secondary structure of protein is stabilised by:
Answer
(A)
Hydrogen bonding
9
Fex2 and Fey3 are known when x and y are :
Answer
(C)
x = F, Cl, Br, I and y = F, Cl, Br
10
Identify the elements X and Y using the ionisation energy values given below :

Ionization energy (kJ/mol)
1$${st}$$ 2$${nd}$$
X 495 4563
Y 731 1450
Answer
(C)
X = Na; Y = Mg
11
JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 133 English
In the above reaction, the reagent ''A'' is :
Answer
(D)
Alkaline KMnO4, H+
12
Arrange the following metal complex/compounds in the increasing order of spin only magnetic moment. Presume all the three, high spin system.

(Atomic numbers Ce = 58, Gd = 64 and Eu = 63)

(a) (NH4)2[Ce(NO3)6]

(b) Gd(NO3)3 and

(c) Eu(NO3)3
Answer
(C)
(a) < (c) < (b)
13
JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Haloalkanes and Haloarenes Question 92 English
Identify the reagent(s) 'A' and condition(s) for the reaction
Answer
(C)
A = Cl2; UV light
14
Statement I : Sodium hydride can be used as an oxidising agent.

Statement II : The lone pair of electrons on nitrogen in pyridine makes it basic.

Choose the CORRECT answer from the options given below :
Answer
(A)
Statement I is false but statement II is true
15
[Ti(H2O)6]3+ absorbs light of wavelength 498 nm during a d $$-$$ d transition. The octahedral splitting energy for the above complex is ____________ $$\times$$ 10$$-$$19 J. (Round off to the Nearest Integer). h = 6.626 $$\times$$ 10$$-$$34 Js; c = 3 $$\times$$ 108 ms$$-$$1
Answer
4
16
A 5.0 m mol dm$$-$$3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm$$-$$1. The molar conductivity of this solution is ___________ mSm2 mol$$-$$1. (Round off to the Nearest Integer).
Answer
14
17
At 25$$^\circ$$C, 50 g of iron reacts with HCl to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is _________ J. (Round off to the Nearest Integer).

[Given : R = 8.314 J mol$$-$$1 K$$-$$1. Assume, hydrogen is an ideal gas] [Atomic mass of Fe is 55.85 u]
Answer
2218
18
The number of orbitals with n = 5, m1 = +2 is ___________. (Round off to the Nearest Integer).
Answer
3
19
A and B decompose via first order kinetics with half-lives 54.0 min and 18.0 min respectively. Starting from an equimolar non reactive mixture of A and B, the time taken for the concentration of A to become 16 times that of B is _________ min. (Round off to the Nearest Integer).
Answer
108
20
In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is __________. (Round off to the Nearest Integer). [Given : Aqueous tension at 287 K = 14 mm of Hg]
Answer
19
21
When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, _________ $$\times$$ 10$$-$$5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).
Answer
525
22
Sulphurous acid (H2SO3) has Ka1 = 1.7 $$\times$$ 10$$-$$2 and Ka2 = 6.4 $$\times$$ 10$$-$$8. The pH of 0.588 M H2SO3 is __________. (Round off to the Nearest Integer).
Answer
1
23
At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is ___________ kPa. (Round off to the Nearest Integer).
Answer
19