JEE MAIN - Chemistry (2021 - 16th March Evening Shift - No. 23)
At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is ___________ kPa. (Round off to the Nearest Integer).
Answer
19
Explanation
$${X_A} = {1 \over {1 + 2}} = {1 \over 3}$$
$${X_B} = {2 \over 3}$$
$$P_A^o = 21kPa$$
$$P_B^o = 18kPa$$
$${P_{total}} = P_A^o{X_A} + P_B^o{X_B}$$
$$ = 21 \times {1 \over 3} + 18 \times {2 \over 3}$$
$$ = 7 + 12$$
$$ = 19 kPa$$
$${X_B} = {2 \over 3}$$
$$P_A^o = 21kPa$$
$$P_B^o = 18kPa$$
$${P_{total}} = P_A^o{X_A} + P_B^o{X_B}$$
$$ = 21 \times {1 \over 3} + 18 \times {2 \over 3}$$
$$ = 7 + 12$$
$$ = 19 kPa$$
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