JEE MAIN - Chemistry (2021 - 16th March Evening Shift - No. 10)
Identify the elements X and Y using the ionisation energy values given below :
| Ionization energy (kJ/mol) | ||
|---|---|---|
| 1$${st}$$ | 2$${nd}$$ | |
| X | 495 | 4563 |
| Y | 731 | 1450 |
X = F; Y = Mg
X = Mg; Y = F
X = Na; Y = Mg
X = Mg; Y = Na
Explanation
Due to 2p6, noble gas electronic configuration, the
second ionisation enthalpy of Na is very high. That’s
why has large difference between IE1, and IE2
Mg+ is 2p6, 3s1.
After the loss of one electron, Mg+ will be formed with noble gas electronic configuration. That’s why has less difference between I.E1 and I.E2, but it's I.E3 is very high.
Mg+ is 2p6, 3s1.
After the loss of one electron, Mg+ will be formed with noble gas electronic configuration. That’s why has less difference between I.E1 and I.E2, but it's I.E3 is very high.
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