JEE MAIN - Chemistry (2021 - 16th March Evening Shift - No. 15)
[Ti(H2O)6]3+ absorbs light of wavelength 498 nm during a d $$-$$ d transition. The octahedral splitting energy for the above complex is ____________ $$\times$$ 10$$-$$19 J. (Round off to the Nearest Integer). h = 6.626 $$\times$$ 10$$-$$34 Js; c = 3 $$\times$$ 108 ms$$-$$1
Answer
4
Explanation
Octahedral splitting energy = $${{hc} \over \lambda }$$
$$ = {{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {498 \times {{10}^{ - 9}}}}$$
$$ = 3.99 \times {10^{ - 19}}J$$
$$ \approx 4 \times {10^{ - 19}}$$
$$ = {{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {498 \times {{10}^{ - 9}}}}$$
$$ = 3.99 \times {10^{ - 19}}J$$
$$ \approx 4 \times {10^{ - 19}}$$
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