JEE Advance - Chemistry (1980)

1
Element X is strongly electropositive and element Y is strongly electronegative. Both are univalent. The compound formed would be
Answer
(A)
X+Y-
2
The modern atomic unit is based on the mass of ______.
Answer
(D)
Carbon-12
3
The total no of electron present in 18 ml of water is ______.
Answer
(C)
6.02 x 10^24
4
M is molecular weight of KMnO4. The equivalent wight of KMnO4 when it is converted into K2MnO4 is
Answer
(A)
M
5
A hydrocarbon contains 10.5 g of carbon per gram of hydrogen. 1 litre of the hydrocarbon at 127oC and 1 atmosphere weighs 2.8 g. Find the molecular formula.
Answer
(B)
C7H8
6
Find
(i) The total number of neutrons and
(ii) The total mass of neutron in 7 mg of 14C
(Assume that mass of neutron = mass of hydrogen atom)
Answer
(A)
The total number of neutrons is 3.01 x 10^20, and the total mass of neutrons is 3.5 x 10^-3 g
7
A mixture contains NaCl and unknown chloride MCl.

(i) 1g of this is dissolved in water. Excess of acidified AgNO3 solution is added to it. 2.567 g of white ppt is formed.

(ii) 1 g of original mixture is heated to 300oC. Some vapours come out which are absorbed in acidified AgNO3 solution, 1.341 g of white precipitate was obtained.

Find the molecular weight of unknown chloride.
Answer
(C)
53.53
8
(a) One litre of a sample of hard water contains 1 mg of CaCl2 and 1 mg of MgCl2. Find the total hardness in terms of parts of CaCO3 per 106 parts of water by weight.

(b) A sample of hard water contains 20 mg of Ca++ ions per litre. How many milli-equivalent of Na2CO3 would be required to soften 1 litre of the sample?

(c) 1 gm of Mg is burnt in a closed vessel which contains 0.5gm of O2.
      (i) Which reactant is left in excess?
      (ii) Find the weight of the excess reactants.
      (iii) How many milliliters of 0.5N H2SO4 will dissolve the residue in the vessel?
Answer
A
B
D
E
9
(i). A sample of MnSO4.4H2O is strongly heated in air. The residue is Mn3O4.

(ii). The residue is dissolved in 100 ml of 0.1N FeSO4 containing dilute H2SO4.

(iii). The solution reacts completely with 50 ml of KMnO4 solution.

(iv). 25 ml of the KMnO4 solution used in step (iii) requires 30 ml of 0.1 N FeSO4 solution for complete reaction.

Find the amount of MnSO4.4H2O present in the sample.
Answer
(B)
1.338 g
10
(a) One litre of a sample of hard water contains 1 mg of CaCl2 and 1 mg of MgCl2. Find the total hardness in terms of parts of CaCO3 per 106 parts of water by weight.

(b) A sample of hard water contains 20 mg of Ca++ ions per litre. How many milli-equivalent of Na2CO3 would be required to soften 1 litre of the sample?

(c) 1 gm of Mg is burnt in a closed vessel which contains 0.5gm of O2.
      (i) Which reactant is left in excess?
      (ii) Find the weight of the excess reactants.
      (iii) How many milliliters of 0.5N H2SO4 will dissolve the residue in the vessel?
Answer
(A)
(a) 2 ppm; (b) 1 milli-equivalent; (c) (i) Mg; (ii) 0.25g; (iii) 166.65 ml
11
Which of the following compounds are covalent?
Answer
(A)
H2
12
The total number of electrons that take part in forming the bond in N2 is
Answer
(C)
6
13
Which of the following is soluble in water?
Answer
(B)
C2H5OH
14
Anhydrous MgCl2 is obtained by hydrated salt with ______.
Answer
(D)
heating in a stream of anhydrous HCl
15
Calcium is obtained by
Answer
(A)
electrolysis of molten CaCl2
16
HCL is added to the following oxides. Which one would give H2O2?
Answer
(C)
BaO2.8H2O
17

Explain the following in not more than two sentenses.

A solution of FeCl3 in water gives a brown precipitate on standing.

Answer
(B)
FeCl3 hydrolyzes in water, producing HCl and a brown precipitate of Fe(OH)3.
18

Compound A is a light green crystalline solid. It gives the following tests :

(i) It dissolves in dilute sulphuric acid. No gas is produced.

(ii) A drop of KMnO4 is added to the above solution. The pink colour disappears.

(iii) Compound A is heated strongly. Gases B and C, with pungent smell, come out. A brown residue D is left behind.

(iv) The gas mixture (B and C) is passed into a dichromate solution. The solution turns green.

(v) The green solution from step (iv) gives a white precipitate E with a solution of barium nitrate.

(vi) Residue D from step (iii) is heated on charcoal in a reducing flame. It gives a magnetic substance E.

Name the compounds A, B, C, D and E.

Answer
(A)
A – Ferrous sulphate (FeSO4·7H2O); B – Sulphur dioxide (SO2); C – Sulphur trioxide (SO3); D – Ferric oxide (Fe2O3); E – Iron (Fe)