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WAEC - Physics (2013 - No. 18)

Ice of mass 10g at 5°C was completely converted to water at 0°C, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg\(^{-1}\)K\(^{-1}\), specific latent heat of fusion of ice = 336 Jg\(^{-1}\)]
105J
3255J
3465J
16821J

解释

Q = ML + MC\(\theta\)

= 10 x 335 + 10 x 2.1 x 5

= 3465J

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