WAEC - Physics (2005 - No. 35)
A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
1.2C
3.3C
3330.0C
12.0000.0C
解释
Q = CV
= 600 x 10-6 x 200 = 1.2C
= 600 x 10-6 x 200 = 1.2C