登入
WAEC - Mathematics (2003 - No. 13)
Evaluate \(\frac{log8}{log\left(\frac{1}{4}\right)}\)
-2
\(\frac{-3}{2}\)
\(\frac{1}{2}\)
4
解释
\(\frac{log8}{log\frac{1}{4}}=\frac{log2^3}{log2^{-2}}=\frac{3log2}{-2log2}=-\frac{3}{2}\)
评论 (0)
登录发表评论
广告
允许 javascript 正确加载此页面
