WAEC - Mathematics (2001 - No. 37)
51o
64o
77o
103o
解释
cos\(\alpha\) = \(\frac{10}{16}\) = 0.625
\(\alpha\) = cos-1(0.625)
= 51.3o
∠PQR = 2\(\alpha\)
= 2(51.3o)
= 102.6
= 103o
\(\alpha\) = cos-1(0.625)
= 51.3o
∠PQR = 2\(\alpha\)
= 2(51.3o)
= 102.6
= 103o