WAEC - Further Mathematics (2022 - No. 14)
If \(x^2+y^2+-2x-6y+5 =0\), evaluate dy/dx when x=3 and y=2.
2
-2
-4
4
解释
\(x^2+y^2+-2x-6y+5 =0\)
When differentiated:
\(x^2+y^2+-2x-6y+5 =0\) → 2x + 2y - 2 - 6 = 0
where x=3 and y=2
2[3] + 2[2] - 8 = 0
6 + 4 - 8 = 2