JEE Advance - Physics (1999)
- 3A particle free to move along the x-axis has potential energy given by $$U\left( x \right) = k\left[ {1 - \exp \left( { - {x^2}} \right)} \right]$$ for $$ - \infty \le x \le - \infty $$, where k is a positive constant of appropriate dimensions. Then回答(D)for small displacement from x = 0, the motion is simple harmonic
