ExamPlay Light Logo
登入

JEE Advance - Mathematics (2000 - No. 15)

For any positive integer $$m$$, $$n$$ (with $$n \ge m$$), let $$\left( {\matrix{ n \cr m \cr } } \right) = {}^n{C_m}$$
Prove that $$\left( {\matrix{ n \cr m \cr } } \right) + \left( {\matrix{ {n - 1} \cr m \cr } } \right) + \left( {\matrix{ {n - 2} \cr m \cr } } \right) + ........ + \left( {\matrix{ m \cr m \cr } } \right) = \left( {\matrix{ {n + 1} \cr {m + 2} \cr } } \right)$$

Hence or otherwise, prove that $$\left( {\matrix{ n \cr m \cr } } \right) + 2\left( {\matrix{ {n - 1} \cr m \cr } } \right) + 3\left( {\matrix{ {n - 2} \cr m \cr } } \right) + ........ + \left( {n - m + 1} \right)\left( {\matrix{ m \cr m \cr } } \right) = \left( {\matrix{ {n + 2} \cr {m + 2} \cr } } \right).$$.

The first equation can be proved using the hockey-stick identity.
The second equation can be derived from the first equation by repeated application and manipulation of binomial coefficients.
Both equations can be proved using mathematical induction.
The first equation is incorrect.
The second equation is incorrect.

评论 (0)

登录发表评论
广告
BrainBehindX Inc Logo
©2026; 供电 BrainBehindX Inc