登入
JEE Advance - Mathematics (1982 - No. 19)
If p, q, r are any real numbers, then
max (p, q) < max (p, q, r )
min (p, q) = $${1 \over 2}\left( {p + q - \left| {p - q} \right|} \right)$$
max (p, q) < min (p, q, r)
none of these
评论 (0)
登录发表评论
广告
允许 javascript 正确加载此页面
