JEE Advance - Mathematics (1979 - No. 6)
(b) Find the area of the smaller part of a disc of radius $$10$$ cm, cut off by a chord $$AB$$ which subtends an angle of at the circumference.
The height of the balloon is given by the expression $$\frac{a}{2b}\sqrt{(a+b)(3b-a)}$$
The area of the smaller part of the disc is approximately 3.91 sq. cm.
The area of the smaller part of the disc is approximately 39.1 sq. cm.
The height of the balloon cannot be determined with the given information.
The area of the smaller part of the disc depends on the radius of the balloon