JAMB - Physics (2009 - No. 9)
If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
6.0 x 10-2J
7.6 x 10-2J
1.8 x 10-2J
6.6 x 10-2J
解释
Work done on a stretched cord
= Average force x extension
= \(\frac{1 \times 10 \times 0.012}{2}\)
= 6.0 x 10\(^{-2}\)J
= Average force x extension
= \(\frac{1 \times 10 \times 0.012}{2}\)
= 6.0 x 10\(^{-2}\)J