JAMB - Physics (1987 - No. 11)
A cube of side 10cm and mass 0.5kg floats in a liquid with only \(\frac{1}{5}\) of its height above the liquid surface. What is the relative density of the liquid?
0.125
0.250
0.625
2.500
解释
Height below liquid = 1 - \(\frac{1}{5}\) = \(\frac{4}{5}\)
volume of cube = 10\(^3\)cm\(^3\)
volume of liquid displaced = \(\frac{4}{5}\) x 1000
= 800cm\(^3\)
density of liquid displaced;
= \(\frac{500}{800}\)
= 0.625
volume of cube = 10\(^3\)cm\(^3\)
volume of liquid displaced = \(\frac{4}{5}\) x 1000
= 800cm\(^3\)
density of liquid displaced;
= \(\frac{500}{800}\)
= 0.625