JAMB - Physics (1986 - No. 8)
A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. if the speed of the object when it has moved 50m from O is 500ms-1, what is the value of F?
0.4N
100.0N
250.0N
1000.0N
解释
F = ma and V2 = U2 + 2aX
F = m\(\frac{(V^2 - U^2)}{2X}\)
= 0.04\(\frac{(500^2 - 0^2)}{2 \times 50}\)
F = 100N
F = m\(\frac{(V^2 - U^2)}{2X}\)
= 0.04\(\frac{(500^2 - 0^2)}{2 \times 50}\)
F = 100N