JAMB - Mathematics (2009 - No. 14)

Determine the value of x for which (x\(^2\) - 1) > 0?

x < -1 or x > 1

-1 < x < 1

x > 0

x < -1

解释

x\(^2\) > 0
(x+1)(x-1) > 0
x = 1 or -1

x < -1 or x > 1

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