JAMB - Mathematics (2005 - No. 25)
Find the equation of the perpendicular at the point (4,3) to the line y + 2x = 5
2y - x = 4
y + 2x = 3
y + 2x = 5
2y - x = 2
解释
Gradient of the line y + 2x = 5 = -2
Gradient of the line perpendicular to
y + 2x + 5 = 1/2
equation of a line perpendicular to
y + 2x = 5 at the point (4, 3)
y - y1 = m(x - x1)
y - 3 = 1/2(x - 4)
2y - 6 = x -4
2y - x = 2
Gradient of the line perpendicular to
y + 2x + 5 = 1/2
equation of a line perpendicular to
y + 2x = 5 at the point (4, 3)
y - y1 = m(x - x1)
y - 3 = 1/2(x - 4)
2y - 6 = x -4
2y - x = 2