JAMB - Mathematics (1984 - No. 40)
In the figure, QRS is a line, PSQ = 35o, SPR = 30o and O is the centre of the circle. Find OQP.
35o
30o
130o
25o
65o
解释
< PSQ = 35o, < SPR = 30o
O is the centre of the circle, PRQ = 65o
< OQP = 90 - 65
= 25o
O is the centre of the circle, PRQ = 65o
< OQP = 90 - 65
= 25o