ExamPlay Light Logo
登入

JAMB - Mathematics (1983 - No. 17)

Simplify log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7
1
\(\frac{7}{6}\)log10 a
zero
10

解释

log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7 = log10 a\(\frac{1}{3}\) + log10\(\frac{1}{4}\) - log10 a\(\frac{7}{12}\)

= log10 a\(\frac{7}{12}\) - log10 a\(\frac{7}{12}\)

= log10 1 = 0

评论 (0)

登录发表评论
广告
BrainBehindX Inc Logo
©2026; 供电 BrainBehindX Inc