WAEC - Physics (2016 - No. 34)
A man and his friend have masses 70kg and 60kg respectively. If they are seated 1.0m apart, calculate the gravitational force of attraction between them. (G = 6.67 x 10-11 Nm2 kg-2)
1.59 x 10-14 N
2.80 x 10-7 N
1.30 x 10-2 N
6.30 x 1013 N
Giải thích
F = \(\frac{GM_1M_}{r^2}\)
= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)
= 2.8014 x 10-7 N
= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)
= 2.8014 x 10-7 N