WAEC - Physics (2014 - No. 9)
A car starts from rest and covers a distance of 40m in 10s. Calculate the magnitude of its acceleration
0.25ms-2
0.80ms-2
3.20ms-2
4.00ms-2
Giải thích
S = ut + \(\frac{1}{2} at^2\)
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2