WAEC - Physics (2009 - No. 4)
A body of volume 0.046m3 is immersed in a liquid of density 980kgm-3 with \(\frac{3}{4}\) of its volume submerged. Calculate the upthrust on the body. [g = 10ms-2]
11.27N
33.81N
112.70N
338.10N
Giải thích
M = D x V
= 980 x 0.046 x \(\frac{3}{4}\) = 33.81kg
upthrust = mg = 33.81 x 10
= 338.1N
= 980 x 0.046 x \(\frac{3}{4}\) = 33.81kg
upthrust = mg = 33.81 x 10
= 338.1N