WAEC - Physics (2001 - No. 34)
2\(\mu F\)
6\(\mu F\)
18\(\mu F\)
216\(\mu F\)
Giải thích
\(\frac{1}{c} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6}\)
= \(\frac{1 + 1 + 1}{6} = \frac{3}{6} = \frac{1}{2}\)
= 2\(\mu F\)
= \(\frac{1 + 1 + 1}{6} = \frac{3}{6} = \frac{1}{2}\)
= 2\(\mu F\)