WAEC - Physics (2001 - No. 32)
The magnitude of the gravitational force between two particles 0.10m apart is 10N. If the distance between them is increased to 0.20m, calculate the magnitude of the new force
40.0N
20.0N
5.0N
2.5N
Giải thích
\(g_1 = \frac{Gm_1m_2}{r^2_1}\)
\(m_1m_2 = \frac{gr^2_1}{G}\)
\(g_2 = \frac{Ggr^2_1}{Gr^2_2} = \frac{10 \times 0.1^2}{0.2^2}\)
= 2.5N
\(m_1m_2 = \frac{gr^2_1}{G}\)
\(g_2 = \frac{Ggr^2_1}{Gr^2_2} = \frac{10 \times 0.1^2}{0.2^2}\)
= 2.5N