WAEC - Physics (1997 - No. 3)
A ball of mass 0.1kg approaching a tennis player with a velocity of 10ms\(^{-1}\),is hit back in the opposite direction with a velocity of 15ms\(^{-1}\). If the time of impact between the racket and the ball is 0.01s, calculate the magnitude of the force with which the ball is hit
5000N
500N
250N
50N
25N
Giải thích
M =0.1kg; F=\(m\left(\frac{v-u}{t}\right) = 0.1\left(\frac{15-(-10)}{0.01}\right)\) F=250N