WAEC - Physics (1991 - No. 15)
A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?
54cm2
273cm2
300cm2
546cm2
600cm2
Giải thích
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = \(\frac{V_1T_2}{T_1}\) = 546cm
V1 - V2 = 54cm
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = \(\frac{V_1T_2}{T_1}\) = 546cm
V1 - V2 = 54cm