WAEC - Mathematics (2021 - No. 7)
Factorize 6pq-3rs-3ps+6qr
3(r -p)(2q + s)
3(p + r)( 2q - 2q - s)
3(2q - s)(p + r)
3(r - p)(s - 2q)
Giải thích
6pq-3rs-3ps+6qr = 3 (2pq - rs - ps + 2qr)
= 3 ({2pq + 2qr} {-ps - rs})
= 3 (2q{ p + r} -s{p + r})
= 3 ({2q - s}{p + r})