WAEC - Mathematics (2019 - No. 7)
Evaluate; \(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)
-\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(\frac{1}{3}\)
-\(\frac{1}{2}\)
Giải thích
\(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)
= \(\frac{\log_3 3^2 - \log_2 2^3}{\log_3 3^2}\)
= \(\frac{2 -3}{2}\)
= \(\frac{-1}{2}\)