WAEC - Mathematics (2009 - No. 24)
If c and k are the roots of 6 - x - x2 = 0, find c + k
2
1
-1
-3
Giải thích
6 - x - x2 = 0
a = -1; b = -1; c = 6
Sum of roots = c + k = -\(\frac{-b}{a}\)
= \(\frac{-(-1)}{-1}\)
= -1
a = -1; b = -1; c = 6
Sum of roots = c + k = -\(\frac{-b}{a}\)
= \(\frac{-(-1)}{-1}\)
= -1