WAEC - Mathematics (2007 - No. 49)
make w the subject of the relation \(\frac{a + bc}{wd + f}\) = g
\(\frac{a + bc - fg}{dg}\)
\(\frac{a - bc + fg}{dg}\)
\(\frac{a + bc - f}{dg}\)
\(\frac{a + bc - dg}{dg}\)
Giải thích
\(\frac{a + bc}{wd + f}\) = g(cross multiply)
a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)
a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)