WAEC - Mathematics (2003 - No. 7)
Simplify \(\frac{4}{a-3}-\frac{1}{a+2}\)
\(\frac{3a+11}{(a-3)(a-2)}\)
\(\frac{3a+11}{(a+3)(a-2)}\)
\(\frac{3a+11}{(a+3)(a+2)}\)
\(\frac{3a+11}{(a-3)(a+2)}\)
Giải thích
\(\frac{4}{a-3}-\frac{1}{a+3}\)
= \(\frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\)
\(\frac{4a+8 -a +3}{(a-3)(a+2)}\)
= \(\frac{3a+11}{(a-3)(a+2)}\)