WAEC - Mathematics (1999 - No. 17)
Simplify \(\frac{4}{x+1}-\frac{3}{x-1}\)
\(\frac{x+7}{x^2 - 1}\)
\(\frac{x-7}{x^2 + 1}\)
\(\frac{x-7}{x^2 - 1}\)
\(\frac{x-11}{x^2 - 1}\)
Giải thích
\(\frac{4}{x+1}-\frac{3}{x-1} \\
=\frac{4x - 4 - 3x - 3}{(x+1)(x-1)}=\frac{x-7}{x^2 - 1}\)