WAEC - Mathematics (1999 - No. 13)
Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)
-22
-14
14
22
Giải thích
Given that m = -3, n = 2, the value of
\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)