WAEC - Mathematics (1998 - No. 21)
If h(m+n) = m(h+r) find h in terms of m, n and r
\(h=\frac{mr}{2m+n}\)
\(h=\frac{mr}{n+m}\)
\(h=\frac{m+n}{n}\)
\(h=\frac{m+n}{m}\)
\(h=\frac{mr}{n}\)
Giải thích
\(h(m+n) = m(h+r)\\
hm+hn=hm+mr\\
hn=mr\\
h=\frac{mr}{n}\)
hm+hn=hm+mr\\
hn=mr\\
h=\frac{mr}{n}\)