WAEC - Further Mathematics (2024 - No. 18)
A body of mass 42 kg increases its speed from 15 ms\(^{-1}\) to 43 ms\(^{-1}\) in 12 seconds. Find the force acting on the body.
203N
150N
98N
52N
Giải thích
Using F = \(\frac{M(u_2 - u_1)}{t}\)
F = \(\frac{42 (43 - 15)}{12}\) = \(\frac{42 \times 28}{12}\) = \(\frac{1176}{12}\) = 98N