WAEC - Further Mathematics (2021 - No. 22)
Given that F\(^1\)(x) = x\(^3\) √x, find f(x)
\(\frac{2x^{9/2}}{9}\) + c
2\(x^{\frac{9}{2}}\) + c
\(\frac{2x^{\frac{5}{2}}}{5}\)
x\(^4\) + c
Giải thích
F1 (x) = x\(^3\) √x = x\(^{7/2}\)
F(x) = \(\frac{x^{7/2 +1}}{7/2 + 1}\) + c
= \(\frac{x^{9/2}}{9/2}\)
= \(\frac{2x^{9/2}}{9}\) + c