WAEC - Further Mathematics (2019 - No. 2)
Solve; \(\frac{P}{2} + \frac{k}{3}\) = 5 and 2p = k = 6 simultaneously
p = -6, k = -6
p = -6, k = 6
p = 6, k = 6
p = 6, k = -6
Giải thích
\(\frac{P}{2} + \frac{k}{3}\) = 5
\(\frac{3p + 2k}{6}\) = 5
2p + 3k = 30
- 2p - k = 6
\(\overline{\frac{4k}{4} = \frac{24}{4}}\)
k = 6
From 2p - k = 6
2p - 6 = 6
\(\frac{2p}{2} = \frac{12}{2}\)
p = 6