WAEC - Further Mathematics (2016 - No. 22)
Given that \(\tan x = \frac{5}{12}\), and \(\tan y = \frac{3}{4}\), Find \(\tan (x + y)\).
\(\frac{16}{33}\)
\(\frac{33}{56}\)
\(\frac{33}{16}\)
\(\frac{56}{33}\)
Giải thích
\(\tan (x + y) = \frac{\tan x + \tan y}{1 - \tan x\tan y}\)
\(\tan x = \frac{5}{12} ; \tan y = \frac{3}{4}\)
\(\tan (x + y) = \frac{\frac{5}{12} + \frac{3}{4}}{1 - (\frac{5}{12} \times \frac{3}{4}})\)
= \(\frac{\frac{14}{12}}{\frac{33}{48}}\)
= \(\frac{56}{33}\)