WAEC - Further Mathematics (2012 - No. 28)
Find the values of x at the point of intersection of the curve \(y = x^{2} + 2x - 3\) and the lines \(y + x = 1\).
(1, -2)
(0, 4)
(2, -3)
(1, -4)
Giải thích
Equate the equation of the curve and the line in order to find their point of intersection ie The values of y in both equations.
\(y + x = 1 \implies y = 1 - x\)
\(x^{2} + 2x - 3 = 1 - x\)
\(x^{2} + 2x + x - 3 - 1 = 0 \implies x^{2} + 3x - 4 = 0\)
\((x - 1)(x + 4) = 0\)
\(x = (1, -4)\)