WAEC - Further Mathematics (2008 - No. 7)
The polynomial \(2x^{3} + x^{2} - 3x + p\) has a remainder of 20 when divided by (x - 2). Find the value of constant p.
8
6
-6
-8
Giải thích
Remainder for f(2) = 20.
\(f(2) = 2(2^{3}) + 2^{2} - 3(2) + p = 20\)
\(16 + 4 - 6 + p = 20\)
\(14 + p = 20\)
\(p = 6\)