WAEC - Chemistry (2017 - No. 11)
The oxidation number of nitrogen in \(Pb(NO_{3})_{2}\) is
+2
+3
+4
+5
Giải thích
\(Pb(NO_{3})_{2}\) = \(+2 +2N + (-2\times 6) = 0\)
= \(2N = 10\)
⇒ \(N = +5\)
\(Pb(NO_{3})_{2}\) = \(+2 +2N + (-2\times 6) = 0\)
= \(2N = 10\)
⇒ \(N = +5\)