WAEC - Chemistry (2014 - No. 15)
The oxidation number of sulphur in Fe2(SO4)3 is
+2.
+3
+4.
+6.
Giải thích
Fe2(SO4)3 = 0
(+3 x 2) 9 3x + (-2 x 4 x 3) = 0
+6 + 3x -24 = 0
+3x - 18 = 0
3 x = 18
x = 18/3 = +6
(+3 x 2) 9 3x + (-2 x 4 x 3) = 0
+6 + 3x -24 = 0
+3x - 18 = 0
3 x = 18
x = 18/3 = +6