WAEC - Chemistry (2006 - No. 15)
The oxidation number of iodine in the iodate ion (IO -3) is
-5
-1
+1
+5
Giải thích
1O3
[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x - 6 = - 1
x = - 1 + 6 = +5
[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x - 6 = - 1
x = - 1 + 6 = +5