JEE Advance - Mathematics (1983 - No. 15)
Evaluate : $$\int {{{\left( {x - 1} \right){e^x}} \over {{{\left( {x + 1} \right)}^3}}}dx} $$
${{{e^x}} over {{{left( {x + 1}
ight)}^2}}} + C$
${{{e^x}} over {{{left( {x - 1}
ight)}^2}}} + C$
${{{e^x}} over {{{left( {x + 1}
ight)}}} + C$
${{{e^x}} over {{{left( {x - 1}
ight)}}} + C$
${{{e^x}left( {x - 1}
ight)} over {{{left( {x + 1}
ight)}^2}}} + C$