JEE MAIN - Physics (2010 - No. 1)
The combination of gates shown below yields
OR gate
NOT gate
XOR gate
NAND gate
Giải thích
The final boolean expression is,
$$X = \overline {\left( {\overline A .\overline B } \right)} = \overline {\overline A } + \overline {\overline B } = A + B \Rightarrow \,\,OR\,gate$$
$$X = \overline {\left( {\overline A .\overline B } \right)} = \overline {\overline A } + \overline {\overline B } = A + B \Rightarrow \,\,OR\,gate$$