JEE MAIN - Chemistry (2004 - No. 4)
What is the equilibrium expression for the reaction
P4 (s) + 5O2 $$\leftrightharpoons$$ P4O10 (s)?
P4 (s) + 5O2 $$\leftrightharpoons$$ P4O10 (s)?
Kc = [P4O10] / 5[P4] [O2]
Kc = 1/[O2]5
Kc = [P4O10] / [P4] [O2]5
Kc = [O2]5
Giải thích
For $${P_4}\left( s \right) + 5{O_2}\left( g \right)\,\rightleftharpoons\,{P_4}{O_{10}}\left( 8 \right)$$
$${K_c} = {1 \over {{{\left( {{O_2}} \right)}^5}}}.$$ The solids have concentration unity
$${K_c} = {1 \over {{{\left( {{O_2}} \right)}^5}}}.$$ The solids have concentration unity