JAMB - Physics (2024 - No. 30)
The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.
4ms\(^{-1}\)
3ms\(^{-1}\)
2ms\(^{-1}\)
1ms\(^{-1}\)
Giải thích
distance between two successive crests of a water wave = \(\lambda\) = 0.25m
Frequency (f) is defined as the number of cycles or oscillations that occur in one second = four complete vertical oscillations in one second = 4Hz
Speed of wave (v) = f x \(\lambda\) = 0.25 x 4 = 1m/s