JAMB - Physics (2024 - No. 29)
A mass of gas at 40mmHg is heated from 298k to 348k at constant volume. Cal the pressure exerted by the gas.
50.21mmHg
46.71mmHg
42.35mmHg
35.12mmHg
Giải thích
From pressure law
\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)
P\(_2\) = \(\frac{P_1 \times T_2}{T_1}\)
P\(_1\) = 40mmHg, P\(_2\) = ?
T\(_1\) = 298k, T\(_2\) = 348k
\(\frac{40}{298} = \frac{P_2}{348}\)
P\(_2\) = \(\frac{40\times348}{298}\) = 46.71mmHg